![The region under the curve y=sqrtx bounded by 0<=x<=4 is rotated about a) the x axis and b) the y axis. How do you sketch the region and find the volumes of The region under the curve y=sqrtx bounded by 0<=x<=4 is rotated about a) the x axis and b) the y axis. How do you sketch the region and find the volumes of](https://useruploads.socratic.org/vTmp53bvR0SGubZomlOb_desmos-graph.png)
The region under the curve y=sqrtx bounded by 0<=x<=4 is rotated about a) the x axis and b) the y axis. How do you sketch the region and find the volumes of
![Area bound by y=sqrt(x) , y=0 and x=4 , rotated about the line x = 8 [solids of revolution] : r/askmath Area bound by y=sqrt(x) , y=0 and x=4 , rotated about the line x = 8 [solids of revolution] : r/askmath](https://preview.redd.it/area-bound-by-y-sqrt-x-y-0-and-x-4-rotated-about-the-line-x-v0-kkjrh8012mja1.png?width=927&format=png&auto=webp&s=b4100172c799c1841b928cad6de3a7712e86c1f7)
Area bound by y=sqrt(x) , y=0 and x=4 , rotated about the line x = 8 [solids of revolution] : r/askmath
2/√(x ) + 3/√(y) =2 and 4/√(x) 9/√(y) = 1, solve the following pair of linear equations by substitution,elimination and cross multiplication method.
![Draw the region bounded by the curves y=sqrt(x), x=4, y=0. Use the washer method to find the volume - YouTube Draw the region bounded by the curves y=sqrt(x), x=4, y=0. Use the washer method to find the volume - YouTube](https://i.ytimg.com/vi/smMjZPgCaec/mqdefault.jpg)
Draw the region bounded by the curves y=sqrt(x), x=4, y=0. Use the washer method to find the volume - YouTube
SOLUTION: y=&#8730;(x+4). find the x and y intercept, make a table of values, and sketch the graph. I tried it and i got 2 as y intercept, but i don't know how
![Use the disk method to find the volume of the region bounded by y=sqrt(x), x =4, y=0, rotated about.. - YouTube Use the disk method to find the volume of the region bounded by y=sqrt(x), x =4, y=0, rotated about.. - YouTube](https://i.ytimg.com/vi/1897f4r-dWs/maxresdefault.jpg)
Use the disk method to find the volume of the region bounded by y=sqrt(x), x =4, y=0, rotated about.. - YouTube
![definite integrals - The region between curves $y= {\sqrt x}$ , $0≤x≤4,y=1,x =4$ is revolved about $y=1$. Find the volume of a generated solid. - Mathematics Stack Exchange definite integrals - The region between curves $y= {\sqrt x}$ , $0≤x≤4,y=1,x =4$ is revolved about $y=1$. Find the volume of a generated solid. - Mathematics Stack Exchange](https://i.stack.imgur.com/v1Gpt.png)
definite integrals - The region between curves $y= {\sqrt x}$ , $0≤x≤4,y=1,x =4$ is revolved about $y=1$. Find the volume of a generated solid. - Mathematics Stack Exchange
![Find the volume of the solid formed by revolving the region bounded by y = (\sqrt{(x)}), y = 1 \ and \ x = 4 about the x-axis. Sketch graph. | Homework.Study.com Find the volume of the solid formed by revolving the region bounded by y = (\sqrt{(x)}), y = 1 \ and \ x = 4 about the x-axis. Sketch graph. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/0303034633242757132562821.jpg)