SOLUTION: how does the graph of the line y=2/3x=1 differ from the graph of the line y=4x+1? a.) y=2/3x+1 is steeper than y=3x-1 b.)y=3x+1 is steeper than y=2/3x+1 c.)y=2/3x+1 and y=3x+1 d
![Graph the function y=2/3x−1. I can't seem to remember how to do this. Can somebody refresh me plz? | Socratic Graph the function y=2/3x−1. I can't seem to remember how to do this. Can somebody refresh me plz? | Socratic](https://useruploads.socratic.org/gRihlQoNS7q1kUS4fOKc_acxAf6.jpg)
Graph the function y=2/3x−1. I can't seem to remember how to do this. Can somebody refresh me plz? | Socratic
![Draw the graphs of the equations x = 3, x = 5 and 2x - y - 4 = 0. Also find the area of the quadrilateral formed by the lines and the x-axis Draw the graphs of the equations x = 3, x = 5 and 2x - y - 4 = 0. Also find the area of the quadrilateral formed by the lines and the x-axis](https://d138zd1ktt9iqe.cloudfront.net/media/seo_landing_files/draw-the-graphs-of-the-equations-x-3-x-5-and-2x-y-4-0-1642655315.png)